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kotykmax [81]
3 years ago
15

A does not equal B and 1/x+1/a=1/b, then x=

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0
1/x + 1/a = 1/b

Multiply both sides by x, then a, then b

x(1 + 1/a) = x(1/b)
x • a • 2 = b • x • a

Divide by x, then a

b = 2
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What is the value of the expression 6^2+3^3?
patriot [66]

Answer:

The value of the expression is 63.

Step-by-step explanation:

I used a calculator to calculate the value of the expression. I hope this helps.

8 0
3 years ago
Read 2 more answers
Write a linear function f with the values f (0) =-1 and f (3)= -10
dmitriy555 [2]

Answer:

The linear function is y = -3x -1.

Step-by-step explanation:

A linear function is given by the formula,

y = (m)x + c, where m is the slope and c is the y intercept of function.

The following two points lie on the graph; (0,-1) and (3,-10)

Inserting this two points we get,

-1 = c

-10 = (m)(3) + c,

solving this two equations we get,

m = -3 and c= -1

Thus, the linear function is given by,

y = -3x -1

5 0
3 years ago
Solve for the missing side to the nearest tenth.<br> 19<br> X<br> 51
telo118 [61]

Answer:

<em>x = 30.2 units</em>

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The ratios of the sides of a right triangle are called trigonometric ratios.

Selecting any of the acute angles, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides and the hypotenuse.

The given right triangle has an angle of measure 51° and its adjacent leg has a measure of 19 units. It's required to calculate the hypotenuse of the triangle.

We use the cosine ratio to calculate x:

\displaystyle \cos\theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 51^\circ=\frac{19}{x}

Solving for x:

\displaystyle x=\frac{19}{\cos 51^\circ}

\displaystyle x=\frac{19}{0.6293}

x = 30.2 units

3 0
3 years ago
Line ℓ1 has the equation
aleksley [76]

Answer:

\sqrt{2} units

Step-by-step explanation:

The Line 1 has equation x + y = 5 ....... (1) , and  

Line 2 has equation x + y = 3 .......... (2)

Now, we have to find the perpendicular distance between line 1 and line 2.

We can say that (3,0) is a point on line 2 as it satisfies the equation (2).

Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula

\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2} units (Answer)

We know that the perpendicular distance from any external point (x_{1},y_{1}) to a given straight line ax + by + c = 0 is given by the formula \frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}.

3 0
3 years ago
On a piece of paper, use a protractor to construct a triangle with angle measures of 20° and 30°.
lesya [120]

Answer:

Acute angle

Explanation:

An acute angle is an angle that measures less than 90° but greater than 0°.

5 0
3 years ago
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