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alukav5142 [94]
4 years ago
9

When transformations are combined, Do they look interesting?

Mathematics
1 answer:
Darya [45]4 years ago
5 0
Im assuming this is a True or false question ive answered the same question and its True.

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How would I calculate the horizontal distance of a parabola?​
maks197457 [2]
X = y2 is the equation for it just plug in the numbers
7 0
2 years ago
After working for 25 hours lammer made $375 after working 40 hours lammer made $600 predict how much will he make after 10 hours
Alex
25hr. 40h. 10hr

375$ 600$ x

25 . 40 . x = 1000
375 . 600 = 225000
225000÷1000
x = 225
3 0
3 years ago
The areas of two similar triangles are 20m2 and 180m2. The length of one of the sides of the second triangle is 12m. What is the
guajiro [1.7K]

Answer:

The corresponding side of the first triangle is 4 m.

Step-by-step explanation:

Area of the first triangle: A1=20 m^2

Area of the second triangle: A2=180 m^2

Lenght of one of the sides of the second triangle: s2=12 m

Corresponding side of the first triangle: s1=?

A1/A2=(s1/s2)^2

Replacing the known values:

(20 m^2)/(180 m^2)=[s1/(12 m)]^2

Simplifying:

2/18=[s1/(12 m)]^2

Simplifying the fraction on the left side of the equation dividing the numerator and denominator by 2:

(2/2)/(18/2)=[s1/(12 m)]^2

1/9=[s1/(12 m)]^2

Solving for s1: Square root both sides of the equation:

sqrt(1/9)=sqrt{[s1/(12 m)]^2}

sqrt(1)/sqrt(9)=s1/(12 m)

1/3=s1/(12 m)

Multiplying both sides of the equation by 12 m:

(12 m)*(1/3)=(12 m)*s1/(12 m)

Simplifying:

(12 m)/3=s1

4 m=s1

s1=4 m

8 0
4 years ago
Read 2 more answers
-2x+11+6x how to solve
max2010maxim [7]
Well to simplify it we combine the x's: 4x+11, then to solve for x: 

4x= -11 
x= -11/4 

:)
6 0
4 years ago
Find the rate of change for 2x+4y=10
Ludmilka [50]

rate of change for 2x+4y=10

here rate of change can be found by finding slope

the general form for slope is y=mx+b

isolating y on the left side:

2x+4y=10

4y=y=\frac{-2x+10}{4} \\-2x+10

from here slope is -1/2

Rate of change =-1/2

6 0
3 years ago
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