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vfiekz [6]
3 years ago
6

Help please! Don’t understand!

Mathematics
2 answers:
cricket20 [7]3 years ago
7 0
6+2-(-1)+(-8)=8+1-8=1
julia-pushkina [17]3 years ago
4 0
Hi there! The answer is 1.

6 + 2 - ( - 1) + ( - 8) =
Keep in mind that the sum of a plus and a minus ends up in a minus. So
+ - = -

Keep in mind that the sum of a minus and a minus ends up in a plus.
- - = +

6 + 2 + 1 - 8 =
Now add from left to right.

8 + 1 - 8 =
Add once more

9 - 8 =
Subtract

1
Hence, the answer is 1.
~ Hope this helps you!
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Evaluate sin105° using the sum and differences identities underdstanding 105°=45°+60°
Galina-37 [17]
\bf \textit{Sum and Difference Identity}
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sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)\\\\
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sin(45^o+60^o)\implies sin(45^o)cos(60^o)+cos(45^o)sin(60^o)
\\\\\\
\cfrac{\sqrt{2}}{2}\cdot \cfrac{1}{2}+\cfrac{\sqrt{2}}{2}\cdot \cfrac{\sqrt{3}}{2}\implies \cfrac{\sqrt{2}}{4}+\cfrac{\sqrt{6}}{4}\implies \cfrac{\sqrt{2}+\sqrt{6}}{4}

check your Unit Circle for those angles.
7 0
3 years ago
A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil
Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 20 children

            r = number of success = none of the 20 children

            p = probability of success which in our case is probability that

                   children are unvaccinated, i.e; p = 13.5%

<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

           P(X = 0)  =  \binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}

                          =  1\times 1 \times 0.865^{20}

                          =  0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

8 0
4 years ago
Question 1
kifflom [539]
Are you sure one -662
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3 years ago
Divide. Write your answer as a decimal.<br><br> 0.459 divided by 0.17 =
Rudik [331]

Answer:

0.459 divided by 0.17 equals 2.7

Step-by-step explanation:

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Step-by-step explanation:

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