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Scorpion4ik [409]
3 years ago
7

i really really really need help with this math question i’m giving away FREE points and BRAINLIEST for correct answer

Mathematics
2 answers:
Travka [436]3 years ago
8 0

B is the correct answer. please mark brainliest.

Sonja [21]3 years ago
3 0
Answer:


B is the correct answer

explanation:
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What are the coordinates of the x-intercept of the equation 2x - 3y = 8?
ludmilkaskok [199]

Answer:

(4;0)

Step-by-step explanation:

y=0

2x-3×0=8

2x=8

x=4

4 0
3 years ago
3 out of every 5 students in Mrs. Wilson's class have brown eyes. There are 20 students in Mrs. Wilson's class. How many of the
Alex787 [66]

Answer:

12

Step-by-step explanation:

So there is 3:5 right, so 20 divided by 5 equals 4, there are four 5's in 20.  Then 4 multiplied by 3 equals 12. So there are 12 students that has BROWN EYES.

<em>Hope I Helped You :)</em>

7 0
2 years ago
Answer the right question
SVETLANKA909090 [29]

Answer:

ok

Step-by-step explanation:

3 0
2 years ago
Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi
Marizza181 [45]

Looks like the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

The series telescopes; consider the kth partial sum of the series,

S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}

S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)

\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}

As k\to\infty, the second term converges to 0, leaving us with

\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}

7 0
3 years ago
What is the lcm of 15 25 9 8.
posledela
Hi !

So,here we have to calculate the least common multiple of the numbers 15,25,9,8.

<span>We have to break down every number as a prime number product:</span>
15 = 3·525 = 5² 9  = 3² 8  = 2³

Then,we have to select <span> common and uncommon numbers at the highest power so:
</span><span>
</span><span>lcm : 2³·3²·5² = 8·9·25 = 1800
</span>




7 0
3 years ago
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