"interverted" or "inverted?"
The vertical height of an inverted cone with base diameter 6 cm and slant height of 6 cm can be found using the Pyth. Thm. Draw or imagine a triangle whose height is h and whose base is 3 cm (not 6) and whose hypotenuse is 6 cm.
Then h^2 + (3 cm)^2 = (6 cm)^2, or h^2 + 9 cm^2 = 36 cm^2, or h^2 = 27 cm^2.
Then the height of the triangle, as well as of the cone, is h = +√27, or
h = +3√3.
13.5
It’s a close guess . Sorry if it’s wrong
The magnitude of YZ is 8.6
<u>Explanation:</u>
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Y( -4, 12)
Z ( 1, 19)
Magnitude of YZ = ?
We know:

On substituting the value we get:

Thus, the magnitude of YZ is 8.6
Answer:

Step-by-step explanation:
- The cross section of a sphere is a circle with area
, where radius is given as 4 - The cross section of the cube is a square with area
, where a is side length of square
The circle area = the square area. Thus we have:

Slope-intercept form is y = mx + b.
In this form, m is slope and b is y-intercept.
Slope is rise over run. The formula for this is (y2-y1)/(x2-x1).
Y-intercept is the value of y when x is equal to 0.
1. Slope = 8 ; Y-intercept = 0
y = mx + b
m = 8 ; b = 0
y = 8x + 0
y = 8x
2. Slope = 1 ; Y-intercept = 2
y = mx + b
m = 1 ; b = 2
y = 1x + 2
y = x + 2
The answer to #1 is y = 8x.
The answer to #2 is y = x + 2.
Hope this helps!