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dalvyx [7]
3 years ago
13

Find the equation of a line perpendicular to -x=4-y that passes through the point (-3,8)

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0

9514 1404 393

Answer:

  y = -x +5

Step-by-step explanation:

Solving the given equation for y, we have ...

  y = x +4

The slope of this line is the coefficient of x: 1. The slope of the perpendicular line will be the opposite reciprocal of this: -1/1 = -1. The y-intercept of the perpendicular line can be found from ...

  b = y -mx = 8 -(-1)(-3) = 5

The perpendicular line has equation ...

  y = -x +5

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Parallel lines m and n are cut by a transversal t. Which two angles are corresponding angles? A. 1 and 5 B. 1 and 6 C. 1 and 2 D
jeka94

Answer:

1 and 5

Step-by-step explanation:

So basically corresponding angles are the angles which lie on the same line of the transversal

And also one of them will be an interior angle and the other a exterior angle

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Which expression is the result of factoring the expression below by taking out its greatest common factor?
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Answer:

Step-by-step explanation:

You need to give us the choices. However, I will try and give you the answer.

The highest common factor is 8

8(x^2 - 3)     This is the answer I think the question expects.

8(x - √3 )(x + √3)  this is also possible

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3 years ago
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4 years ago
In x2 + 7x + 5 = 0,
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6 0
3 years ago
A test-preparation company advertises that its training program raises SAT scores by an average of at least 30 points. A random
aniked [119]

Answer:

(a) Null Hypothesis, H_0 : \mu \geq 30 points

    Alternate Hypothesis, H_A : \mu < 30 points

(b) Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

Step-by-step explanation:

We are given that a test-preparation company advertises that its training program raises SAT scores by an average of at least 30 points.

A random sample of test-takers who had completed the training showed a mean increase smaller than 30 points.

Let \mu = <u><em>average SAT score.</em></u>

(a) So, Null Hypothesis, H_0 : \mu \geq 30 points

Alternate Hypothesis, H_A : \mu < 30 points

Here, the null hypothesis states that the training program raises SAT scores by an average of at least 30 points.

On the other hand, the alternate hypothesis states that test-takers who had completed the training showed a mean increase smaller than 30 points.

(b) Type I error states the probability of rejecting the null hypothesis given the fact that null hypothesis is true.

According to the question, the Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

The consequence of a Type I error is that we conclude the test-takers have low SAT scores but in actual they have an SAT score of at least 30 points.

7 0
3 years ago
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