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sveta [45]
3 years ago
9

A business sells kicking tees by mail for 3 each the shipping charge is 5 the function p=n+5 shows how the number of tees n rela

ted to the price p you will pay find the price you will pay if you buy 2 3 or 4 tees
Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

<u>Answer: </u>

When you buy 2 , 3 and 4 tees , price you pay are 10.33 unit price , 13 unit price and 15.667 unit price respectively.

<u>Solution: </u>

Information provided in the question seems to be less . so assuming following two things.

1)Given function p = n + 5 do not include shipping cost as shipping cost is also dependent on number of tees.

2)If shipping charges for 3 tees is 5 , then shipping charges of 1 tee is \frac{5}{3}

When you buy 2 tees , n = 2

Price = p = n+5 = 2+5 = 7

Shipping charges =( \frac{5}{3} ) x 2 = \frac{10}{3}

So total price you pay for two tees = 7 + (\frac{10}{3}) = 7 + 3.3333 = 10.3333 unit price.

When you buy three tees , n = 3  

Price = p = n+5 = 3+5 = 8

Shipping charges =( \frac{5}{3} ) x 3 = 5

So total price you pay for two tees = 8 + 5 = 13 unit price.

When you buy four tees, n = 4  

Price = p = n+5 = 4+5 = 9

Shipping charges =( \frac{5}{3} ) x 4 = \frac{20}{3}

So total price you pay for two tees = 9 + (\frac{20}{3}) = 47/3 = 15.667 unit price.

Hence when you buy 2 , 3 and 4 tees , price you pay are 10.33 unit price , 13 unit price and 15.667 unit price respectively.

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A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
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Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

<u>when the angle is 30 degrees</u>

tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

d1 = \frac{6000}{0.577}

d1 = 10392.3 meters

<u>when the angle is 60 degrees</u>

tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

d2  = \frac{6000}{1.732}\\

d2 = 3464.1 meters

<u>distance travelled by aircraft in 1 min is  </u>

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

<u>Now converting to m/sec</u>

=>\frac{6928.2}{60}

=>115.47 m/sec

4 0
3 years ago
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