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asambeis [7]
3 years ago
7

Solve the following 3 × 3 system. Enter the coordinates of the solution below.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Step-by-step explanation:

2x - 3y - 2z = 4

[2] x + 3y + 2z = -7

[3] -4x - 4y - 2z = 10

Solve by Substitution :

// Solve equation [2] for the variable x

[2] x = -3y - 2z - 7

// Plug this in for variable x in equation [1]

[1] 2•(-3y-2z-7) - 3y - 2z = 4

[1] - 9y - 6z = 18

// Plug this in for variable x in equation [3]

[3] -4•(-3y-2z-7) - 4y - 2z = 10

[3] 8y + 6z = -18

// Solve equation [3] for the variable z

[3] 6z = -8y - 18

[3] z = -4y/3 - 3

// Plug this in for variable z in equation [1]

[1] - 9y - 6•(-4y/3-3) = 18

[1] - y = 0

// Solve equation [1] for the variable y

[1] y = 0

// By now we know this much :

x = -3y-2z-7

y = 0

z = -4y/3-3

// Use the y value to solve for z

z = -(4/3)(0)-3 = -3

// Use the y and z values to solve for x

x = -3(0)-2(-3)-7 = -1

Solution :

{x,y,z} = {-1,0,-3}

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Answer: x = 2921, y = 579

Step-by-Step Explanation:

I am assuming that we just have to Solve for ‘x’ and ‘y’.

‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles

=> x + y = 3500 (Eq. 1)
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Adding Eq. 1 and Eq. 2, we get :-

2x = 3500 + 2342
2x = 5842
x = 5842/2
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Therefore, x = 2921

Substitute value of ‘x’ in Eq. 1 :-

x + y = 3500
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y = 3500 - 2921
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Therefore, y = 579

Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579
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