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iVinArrow [24]
3 years ago
3

In Triangle RST, Angle R = 63 degrees, angle T=90 degrees, Side RS =23, side st = 10.4. Which ratios are correct.csc63=23/rt, se

c 63=23/10.4, and cot 27=10.4/RTcsc63=23/rt, sec 27=10.4/23, and cot63=10.4/rtcsc63=23/rt, sec 27= 23/10.4, and cot 63 = rt/10.4csc63=23/rt, sec 63=10.4/23, and cot27=RT/10.4

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

The correct ratios are: cse 27=23/RT, sec 27= 23/10.4 and cot 63 = RT/10.4

In triangle RST, angle T= 90° and angle R= 63°

As the total of all angle in any triangle is 180°, so the measure of the angle S = 180°- (90°+63°)

S= 180°- 153°

S= 27°

According to the rule of trigonometric ratios,

cse(θ) = \frac{hypotenuse}{opposite}

sec(θ) = \frac{hypotenuse}{adjacent }

cot(θ) = \frac{adjacent}{opposite}

In respect of angle R (63°), side RS(23) is hypotenuse , ST(10.4) is opposite and RT is adjacent.

So, cse(63°) = \frac{23}{10.4}

sec(63°) = \frac{23}{RT}

cot(63°) = \frac{RT}{10.4}

Now, in respect of angle S(27°), hypotenuse is RS(23), adjacent is ST(10.4) and opposite is RT.

So, cse(27°) = \frac{23}{RT}

sec(27°) = \frac{23}{10.4}

cot(27°) = \frac{10.4}{RT}

Greeley [361]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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