Answer:
The probability that the student's IQ is at least 140 points is of 55.17%.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
University A: 
a) Select a student at random from university A. Find the probability that the student's IQ is at least 140 points.
This is 1 subtracted by the pvalue of Z when X = 140. So



has a pvalue of 0.4483.
1 - 0.4483 = 0.5517
The probability that the student's IQ is at least 140 points is of 55.17%.
For this case we have the following number:
105,159
By definition we have:
thousand place: five-digit number greater than zero.
On the other hand we have as a rule:
When the previous number is greater than or equal to five, then the next number increases by one.
So we have to round off to the nearest ten thousand:
105,159 = 110,000
Answer:
105,159 rounded to the nearest ten thousand is:
105,159 = 110,000
8-4x=0
-4x=-8
x=2
you mean like this?
Answer:
- 3 and 69/70
Step-by-step explanation:
3 ÷ 5(6 × 7) - 4
3 ÷ 5(40) - 4
3 ÷ 210 - 4
1/70 ÷ 4
- 3 and 69/70
Answer:
$7,865,000 + (Claire's cases)
Step-by-step explanation:
Euro 2,500,000 x 1.13 = $2825000
£4,000,000 x 1.26 = $5040000
$5040000 + $2825000 = $7865000