Answer:
Average rate of change over the interval 2<= x <= 5:
y = 3x + 5: 3
y = 3x^2 + 1: 21
y = 3^x: 78
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Step-by-step explanation:
2<= x <= 5
Average rate of change over the interval 2<= x <= 5:
<u>y = 3x + 5</u>
y(5) = 3(5) + 5 = 20
y(2) = 3(2) + 5 = 11
Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>
<u />
<u>y = 3x^2 + 1</u>
y(5) = 3(5^2) + 1 = 75 + 1 = 76
y(2) = 3(2^2) + 1= 13
Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>
<u />
<u>y = 3^x</u>
y(5) = 3^5 = 243
y(2) = 3^2 =9
Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>
The speed would be 158.4fps and the parachutist would fall 2,376 feet during 15 seconds.
Answer:
Hi! The nswer to your question is m = 1
Step-by-step explanation:
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You would take 320 and multiply it by .60 and you would get 192. So the answer is B) $192.
