All categories

3 years ago

I need help please.

Mathematics

1 answer:

Zarrin [17]3 years ago

3 0

Answer:

i think this is it

Step-by-step explanation:

the answer i got is just 55

You might be interested in

Reba needs to simplify the expression below.

lawyer [7]

Answer:

6.5

Step-by-step explanation:

6.5+(3.5*2)-7/3

6.5+(7-7)/3

6.5+0/3

6.5+0

6.5

5 0

3 years ago

Three brothers share 2 sandwiches equaly. how much of sandwich does brother get?

Pachacha [2.7K]

They must split one with the ,2 bros and the other one gets a whole one I think let me check.......

3 0

2 years ago

Read 2 more answers

Find the domain & range of the relation<br><br> {(-5,13), (6,18), (2,-7), (1,4), (-3,-1)}

Neporo4naja [7]

Answer:

Domain: -5,6,2,1,-3

Range: 13,18,-7,4,-1

Step-by-step explanation:

Domain is the independent value/ x / input

Range is the dependent value/ y / output

5 0

1 year ago

PLEASE HELP IT IS URGENT FOR GEOMETRY DO NOT WASTE ANSWERS WILL MARK BRAINLIEST

Anton [14]

Answer:

Last one

Step-by-step explanation:

In order to have a perpendicular bisector, everything needs to be even and connected.

Really hope this helps!

6 0

2 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

2 years ago