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sveta [45]
2 years ago
11

if w represents the width of a rectangle that is 28 inches long with a perimeter of 110 inches, the best algebraic representatio

n of the rectangle's perimeter is in terms of w
Mathematics
1 answer:
almond37 [142]2 years ago
7 0

Answer:

Width=27inches

Step-by-step explanation:

Width=w

Length=28 inches

Perimeter=110 inches

Perimeter of a rectangle=2(length+width)

110=2(28+w)

110=56+2

110-56=2w

54=2w

Divide both sides by 2

54/2=2w/2

27=w

Therefore,

Width=27inches

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Mark studies a group of 30 whales. If each whale weighed approximately 3.8 x 105 pounds, find the total weight of all 30 whales.
Yakvenalex [24]

Answer:

= 1.14 \times 10^{7}pounds

Step-by-step explanation:

If each whales weighed

3.8 \times  {10}^{5}

Then 30 whales weighed

30 \times 3.8 \times  {10}^{5}

=114 \times {10}^{5}

= 1.14 \times 10^{2}  \times {10}^{10}

Applying the law of indices we obtain

= 1.14 \times 10^{(2+ 5)}

=1.14 \times 10^{7}pounds

6 0
3 years ago
Select all the sets of numbers that are possible values for x in the inequality, x>- 2.
lana66690 [7]

Answer:

{-1, 0,5}

Step-by-step explanation:

3 0
2 years ago
C equals 2 pi r​; Cequals62.8 ​(Circumference of a​ circle)
tatuchka [14]

Answer:

about 10

Step-by-step explanation:

62.8 = 2 pi r/2

62.8/2 = pi r

31.4/pi = pi r/pi

about 10 = r

3 0
2 years ago
A grosry storehas adisplay that has 60 oranges and 16 apples. what is the ratio of oranges to apples
ki77a [65]

Answer:

30:16-15:8 That is simplified and I divided it by two.

6 0
2 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
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