Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
Answer:
<h2>44 ft²</h2><h2 />
Step-by-step explanation:
A1 = 2(5 x 2) = 20
A2 = 8 x 3 = 24
total = 20 + 24
= 44 ft²
Joel's work makes $9.50/ hr. During the 2 Day, 11 hrs shift, he earns a total of $217.55 but spends a cash of $9 on his bus. Therefore, the money left is $208.55. While on his 4 day, 6 hrs shift, he earns a total of $228 but spends $18, with a total money of $210. The option that he should take to make the most money is the 4 days for 6 hrs shift.
Answer:
its 96 hope this helps!
Step-by-step explanation:
it's 96 because 128-(128/8)=96
