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4 years ago

13

In this system of linear equations with no solution

1 answer:

Ksivusya [100]4 years ago

3 0

Two line with the same slope are parallel, if two parallel lines have a different y-intercept they will never cross each other.

(Any two lines with different slopes will always intersect at some point)

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What is the absolute value of <br> –18<br> 19<br> ?<br><br> Write your answer as a fraction.

fenix001 [56]

Answer:

$\frac{18}{19}$

Step-by-step explanation:

The absolute value of a number is how far away it is from 0 on the number line. Even though $\frac{-18}{19}$ is a negative number, the absolute value wouldn't be $\frac{-18}{19}$ , because distance can't be negative. Hence the absolute value of $\frac{-18}{19}$ is $\frac{18}{19}$ .

3 0

3 years ago

Part ?? of i need these

masha68 [24]

The answer is
R = 74
Q = 32
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4 0

3 years ago

Read 2 more answers

Find the sum or difference (2c-4)+(5c+11)

laiz [17]

Remove parentheses
2c - 4 + 5c + 11
Combine like terms
Answer: 7c + 7

7 0

4 years ago

What is 10 to the power of 9 times 2.64

KIM [24]

Solution: 10∧9 x 2.64 = n

Answer: 2,640,000,000

8 0

3 years ago

Given cosine of x is equal to negative square root of 3 over 2 comma what is the value of cos(x π)?

slamgirl [31]

Value of cos(x+π) = $\bold{\frac{\sqrt{3} }{2}}$

Given cosine of x = $-\frac{\sqrt{3} }{2}$

i.e., cos(x) = $-\frac{\sqrt{3} }{2}$

Also cos( $\frac{\pi}{6}$ ) = $\frac{\sqrt{3} }{2}$ . So x = $\frac{\pi}{6}$ .

We need to find cos(x+π) = cos( $\frac{7\pi}{6}$ ).

But its value is not easy to find. So we use trigonometric formulas.

We have the trigonometric formula, cos (x+π) = - cos(x) = - $-\frac{\sqrt{3} }{2}$ = $\bold{\frac{\sqrt{3} }{2}}$

Cos(x+π) lies in the 3rd quadrant. So there cosine has negative values. That is why, cos (x+π) = - cos(x).

Learn more about Cos(x+π) trigonometric formula at brainly.com/question/12243383

#SPJ4

7 0

2 years ago