All categories

1 year ago

Find the quadratic equation with integral coefficients having roots 6 and 2.

Mathematics

1 answer:

ludmilkaskok [199]1 year ago

4 0

The quadratic equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

<h3>How to determine the quadratic equation?</h3>

The roots are given as:

x = 6 and x = 2

Rewrite as:

x - 6 = 0 and x - 2 = 0

Multiply both equations

(x - 6)(x - 2) = 0 * 0

Evaluate the product

x^2 - 6x - 2x + 12 = 0

Evaluate the difference

x^2 - 8x + 12 = 0

Hence, the equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

Read more about quadratic equations at:

brainly.com/question/10449635

#SPJ1

You might be interested in

If the diagonals of a quadrilateral divide each other proportionally then it is a

Artist 52 [7]

Answer:

Step-by-step explanation:

trapezium

<h2>If the diagonals of a quadrilateral divide each other proportionally, then prove that the quadrilateral is a trapezium.</h2>

3 0

2 years ago

What is the approximate perimeter of a semicircle with a radius of 9mm?

Cerrena [4.2K]

Act like it's a whole circle and find the perimeter, then divide by 2.

P = 2 * pi * r

P = 2 * 3.14 * 9

P = 56.52

Now divide by 2:

P = 28.26

3 0

3 years ago

Read 2 more answers

What’s the greatest common factor of 12x^2+9x^3-6x^4

VikaD [51]

$12x^2+9x^3-6x^4\\\\LCD(12,\ 9,\ 6)=3\\\\LCD(x^2,\ x^3,\ x^4)=x^2\\\\12x^2=(3x^2)(4)\\9x^3=(3x^2)(3x)\\-6x^4=(3x^2)(-2x^2)\\\\GCF\ of\ 12x^2+9x^3-6x^4\ is\ equal\ \boxed{3x^2}\\\\12x^2+9x^3-6x^4=(3x^2)(4+3x-2x^2)$

7 0

3 years ago

A company is testing and comparing two lightbulb designs. The box plots show the number of hours that each lightbulb design last

Marrrta [24]

Answer:

Design B bulbs will likely last longer than design A bulbs

Step-by-step explanation:

The B box part spans higher numbers than the A box and the median of B bulbs is higher than median of the A bulbs.

7 0

3 years ago

Read 2 more answers

What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction

Tcecarenko [31]

The product of the expression $(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}$ is the expression $\frac{2}{k+2}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

$(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}$

The product of the expression $(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}$ is the expression $\frac{2}{k+2}$

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0

2 years ago