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1 year ago

Find the quadratic equation with integral coefficients having roots 6 and 2.

Mathematics

1 answer:

ludmilkaskok [199]1 year ago

4 0

The quadratic equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

<h3>How to determine the quadratic equation?</h3>

The roots are given as:

x = 6 and x = 2

Rewrite as:

x - 6 = 0 and x - 2 = 0

Multiply both equations

(x - 6)(x - 2) = 0 * 0

Evaluate the product

x^2 - 6x - 2x + 12 = 0

Evaluate the difference

x^2 - 8x + 12 = 0

Hence, the equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

Read more about quadratic equations at:

brainly.com/question/10449635

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3/7+-5/11+-5/14+3/11

Pachacha [2.7K]

Answer:

Hey!

Your answer is $1\frac{5}{8}$ !

Step-by-step explanation:

Also can be written as 41/8!

HOPE THIS HELPED!

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3 years ago

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The bases of a right prism are isosceles trapezoids with bases of 10 ft and 18 ft

likoan [24]

Answer:

540 ft^2.

Step-by-step explanation:

The area of the trapezoid = h/2 (10 + 18) = 14h.

By Pythagoras the height h = √(5^2 - 4^2) = 3.

So the area of the 2 trapezoidal bases = 2 * 14*3

= 84 ft^2.

Now we calculate the area of the four lateral rectangular sides:

= 10*12 + 18*12 + 2*5*12

= 456 ft^2.

Total area = 456 + 54

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3 years ago

What is the slope of a line that is parallel to the line y=3/4x+2

stepladder [879]

If two lines are parallel to one another, then their slopes are identical. The slope in the line above is 3/4. Therefore, a line parallel to that line will also have a slope of 3/4, it will just have a different y-intercept.

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3 years ago

4/5 is 3 3/5 of what number

tamaranim1 [39]

Let the number be x.
3 3/5 of x = 4/5
18/5x = 4/5
x = 4/5 x 5/18
x = 4/18 = 2/9

The number is 2/9

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3 years ago

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Points A and B are to be mapped onto a number line according to two equations. The solutions to the equation 2/3A=-24 is the coo

Ymorist [56]

Answer:

$\boxed{A=-36} \\ \\ \boxed{B=4}$

Step-by-step explanation:

In mathematics, a number line is graph of a straight line that shows a representation of real numbers. In this problem, points A and B are to be mapped onto a number line according to two equations. So we can find these two points by isolating A from the first equation and B from the second one as follows:

$\frac{2}{3}A=-24 \\ \therefore A=\frac{3(-24)}{2} \\ \\ \therefore \boxed{A=-36}$

$20=\frac{-B}{0.2} \\ \\ \therefore B=-(0.2)(20) \\ \\ \therefore \boxed{B=4}$

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3 years ago