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laiz [17]
2 years ago
5

Find the quadratic equation with integral coefficients having roots 6 and 2.

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
4 0

The quadratic equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

<h3>How to determine the quadratic equation?</h3>

The roots are given as:

x = 6 and x = 2

Rewrite as:

x - 6 = 0 and x - 2 = 0

Multiply both equations

(x - 6)(x - 2) = 0 * 0

Evaluate the product

x^2 - 6x - 2x + 12 = 0

Evaluate the difference

x^2 - 8x + 12 = 0

Hence, the equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0

Read more about quadratic equations at:

brainly.com/question/10449635

#SPJ1

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I am 21 years old my father is 3 times my age how old eill i be when my father is 40
DENIUS [597]

Answer:

Well the answer is 13.3 so 13 years old

Step-by-step explanation:

(F,Y) = (63,21)

Y3=F so F/3=y

so

F= 40

Y=?

40/3=Y

40/3=13.3

4 0
3 years ago
Read 2 more answers
What would the answer be to 4x-6y=36 graphed
xz_007 [3.2K]

Answer:

  see the attachment

Step-by-step explanation:

It is convenient to graph this equation using the x- and y-intercepts.

The x-intercept is found where y=0, so ...

  4x = 36

  x = 9

The y-intercept is found where x=0, so ...

  -6y = 36

  y = -6

<em>Graph the two points (9, 0) and (0, -6) and draw a line through them</em>. The graph is shown below.

8 0
3 years ago
Help me now or else.
ivann1987 [24]

Answer: c. -3.8

Step-by-step explanation:

-9 1/5-10+2/5+2(14 1/2-70 simplifies to -46/5-10+2/5+2(29/2-7)

reduce numbers: -46/5-10+2/5+2x15/2

-46/5-10+2/5+15

-44/5+5= -19/5 = -3.8

7 0
3 years ago
Angle Number<br> Measure<br> 1<br> 2<br> 13<br> 1<br> 1267<br> 2<br> 3
Serggg [28]

Answer:

∠1=54°

∠2=54°

∠3 = 126°

Step-by-step explanation:

We need to find ∠1, 2 and 3

Since a traversal cut parallel lines we would use supplementary angles , congruent angles rules to solve the problem.

Angle 1 and 126 are supplementary angles.

They add up to make 180

So, ∠1 + 126 = 180

∠1 = 180-126

∠1 =54

We get ∠1=54°

Now, ∠1 ≅ ∠2, because they are corresponding angles and if traversal cut parallel lines, corresponding angles are congruent.

So ∠1 ≅ ∠2 therefore, ∠2=54°

Now, for finding measure for ∠3, we know that 126 and ∠4 are corresponding angles and corresponding angles are congruent.

So, ∠4 = 126°

We know that ∠3 and ∠4 are vertical angles.

And if traversal cut parallel lines, vertical angles angles are congruent.

So, ∠3 = 126°

8 0
3 years ago
What is the measure of the third angle?
Shtirlitz [24]

Answer:

45° is your required answer...

4 0
3 years ago
Read 2 more answers
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