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Alchen [17]
3 years ago
8

Addison was given a gift card for a coffee shop. Each morning, Addison uses the card to buy one cup of coffee. Each cup of coffe

e costs $3 and after buying 4 cups of coffee, the card had a $3 remaining balance. Write an equation for A,A, in terms of x,x, representing the amount money remaining on the card after buying xx cups of coffee.
Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

A=−3x+15

Step-by-step explanation:

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Explain how to use the distributive property to find the product 3 x 4 1/5
NikAS [45]

Answer:

12.6

Step-by-step explanation:

The answer is 12.6 and here is the explanation of using the Distributive Property. Because we are multiplying a whole number by a mixed number, we have to multiply the whole number by the whole number in the mixed number and then multiply the whole number by the fraction. In this case, we have 3 x 4 1/5. We multiply 3x4=12 first, and then we multiply 3x1/5 to get 0.6. 12+0.6=12.6. Hope it helps!

5 0
3 years ago
What is the value of the expression 1/2(6x9x1)+15
Vanyuwa [196]

Answer:

the answer of the expression is 42

Step-by-step explanation:

PEMDAS parenthesis are first so we start out with 6x9x1 and the answer to that is 54, next is MULTIPLICATION so we take 1/2 times 52 which is 27 then next is ADD so we add 15 and the answer is 42

5 0
3 years ago
F = 0.272727... <br> 100f = (100) (0.272727...) <br> 100f = ?
olya-2409 [2.1K]
100f = 27.272727.....
5 0
2 years ago
Read 2 more answers
Complete the following sentence using the correct term. <br> 14 is a ________ of 7 and 14.
Sidana [21]

Answer:Complete the following sentence using the correct term.

14 is a ________ of 7 and 14.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th
bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0
3 years ago
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