Answer:
sorry can´t understand langues
Explanation:
cant
Python is the correct answer
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
There isn't enough info for me to answer this with complete confidence XD.
You can try drinking herbal tea if you're having trouble sleeping.