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3 years ago

I need help with this math question

Mathematics

1 answer:

algol133 years ago

8 0

Third option. The letter has neither rotate or symmetry

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Which one is it? Please help

nevsk [136]

Answer:

Step-by-step explanation:

I just did it and got it right

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2 years ago

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Someone please talk to me i'm having a horrible day

vovangra [49]

Answer:

You are a great earthling Congrats Earthling you rock

Step-by-step explanation:

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3 years ago

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FUNCTION OR NOT /// ALGEBRA I

guapka [62]

Answer:

First figure: The graph is not a function

Second figure:

Statement 1: It is false

Statement 2: It is false

Statement 3: It is right

Step-by-step explanation:

First graph is not a function.

The domain of it is ⇒ 0 ≤ x < 3 , 3 < x ≤ 6 , 6 ≤ x < 9

From the domain ⇒ x = 6 has two corresponding values of y⇒ 3 and 4

∴ It is not a function because every x must have one and only one

corresponding value of y

Second figure

{(3 , 6) , (4 , 6) , (5 , 7) , (6 , 8) , (7 , 10) , (8 , 10)}

Statement 1: It is false because we use x-value to check function or not.

The relation is a function because every x-value has one corresponding

y-value

Statement 2: It is false because 3 ≤ x ≤ 8 means we will use for x all real numbers from 3 to 8 not only the integers 3 , 4 , 5 , 6, ,7 , 8

The domain of this function is { 3 , 4 , 5 , 6 , 7 , 8 }

Statement 3: It is right because the range is the y-value and all the y-value in the function are 6 , 7 , 8 , 10

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2 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$

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3 years ago

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The vertex of the parabola below is at the point (1,-3). Which of the equations

kramer

Answer:

Step-by-step explanation:

A. X=-3(4-1)

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2 years ago

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