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3 years ago

13

What is the length of the line?

1 answer:

Dafna1 [17]3 years ago

8 0

the answer is c because it’s not an exact number, but it’s still reasonable considering it’s greater than 6 but still less than 7

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yaroslaw [1]

C. Every y-value is twice the square of its x-value

3 0

3 years ago

Here's another geometry thing I suck at...

solniwko [45]

A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180. Subtracting 116 from both sides, we have d = 64.

By the same theorem, c + 98 = 180; subtracting 98 from both sides, we have c = 82.

Inscribed angles are equal to 1/2 the measure of the intercepted arc. Using this, we have

116 = 1/2(a+99)

Multiplying both sides by 2, we have
232 = a+99

Subtract 99 from both sides:
232 - 99 = a + 99 - 99
133 = a

We also have that
82 = 1/2(133+b)

Multiplying both sides by 2, we have:
164 = 133 + b

Subtract 133 from both sides:
164 - 133 = 133 + b - 133
31 = b

6 0

3 years ago

A manufacturer produces widgets that are packaged in boxes of 100. The probability of a widget being defective is 0.021. Find th

gavmur [86]

Answer:

$\=x=2.1$

$\sigma=2.03$

Step-by-step explanation:

From the question we are told that:

Sample size $n=100$

Probability of a defective widget $P=0.021$

Generally the equation for binomial trial is mathematically given by

$q=1-p$

$q=1-0.021$

$q=0.979$

Since X is binomial random variable with functions of n and p,The equation of mean \=x

$\=x=E(x)$

Where

$E(x=n*p)$

$\=x=100*0.021$

$\=x=2.1$

Generally the equation for variance \sigma is mathematically given by

$\sigma=\sqrt{nqp}$

$\sigma=\sqrt{200*0.021*0.979}$

$\sigma=2.03$

7 0

2 years ago

Set up the characteristic equation, which is given by r2 − 5r − 6 = 0. The roots of this equation are given by r1 = 6 and r2 = −

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

From your characteristic equation, your recursive equation is

$f(n+2) = 5 f(n=1) +6f(n)$

the general solution:

$f(n) = A6^n + B(-1)^n$

The initial conditions are

$f(0) =1 ~~~and~~~ f(1) = 3$

For f(0) = 1, that is

$f(0) = A6^0 + B(-1)^0 = A+ B=1 (*)$

For f(1) = 3, that is

$f(1) = A6^1 + B(-1)^1 = 3$

$6A- B = 3 (**)$

From (*) and (**) you solve for A and B

you have A = 4/7 and B= 3/7

Replace A, B into the general one, you have the particular solution for the given condition

$f(n) = 4/7 *6^n +3/7*(-1)^n$

4 0

3 years ago

is the relationship shown in the table proportional? if so use it to complete a proportions web. if not, explain why.

irakobra [83]

Answer:

No, because it doesn't have a constant pattern and the ratios are nonequivalent

6 0

3 years ago

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