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melamori03 [73]
4 years ago
6

Here's another geometry thing I suck at...

Mathematics
1 answer:
solniwko [45]4 years ago
6 0
A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180.  Subtracting 116 from both sides, we have d = 64.

By the same theorem, c + 98 = 180; subtracting 98 from both sides, we have c = 82.

Inscribed angles are equal to 1/2 the measure of the intercepted arc.  Using this, we have

116 = 1/2(a+99)

Multiplying both sides by 2, we have 
232 = a+99

Subtract 99 from both sides:
232 - 99 = a + 99 - 99
133 = a

We also have that 
82 = 1/2(133+b)

Multiplying both sides by 2, we have:
164 = 133 + b

Subtract 133 from both sides:
164 - 133 = 133 + b - 133
31 = b
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Step-by-step explanation:

$ 86,000 lies in the category $84201 - $ 160725

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4 years ago
Shirley picked out a kite for $3.50. If she gave the family a ten dollar bill, what is the fewest number of bills and coins that
Aleonysh [2.5K]

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4 0
3 years ago
One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function
elena-s [515]

Answer:

The other zeros are -2 and 3.

Step-by-step explanation:

As 1 is a zero then (x - 1) is a factor so we divide:

x - 1 )x^3-2x^2-5x+6(x^2-x-6

        x^3-x^2

              -x^2-5x

              -x^2+x

                      -6x+6    

                      -6x+6

                       ...........

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7 0
3 years ago
Read 2 more answers
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
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