Answer:
A. 0.22
B. 0.18
C. 0.25
D. 0.244
Step-by-step explanation:
S = {51 to 100} = 50
The sample space S contains values from 51 to 100 which is a total of 50 different values.
A.
Probability of A (lies between the values of 90 to 100 = 11).
11/50 = 0.22
B.
For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.
9/50 = 0.18
C.
For student to get c, (70 to 79) a total of 10 values: 10/50 = 0.20
P(student did not get C) = 1-0.20 = 0.80
To get B, ( 80 to 89)
10/50 = 0.20
Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25
D.
Probability of passing lies between 60 to 100 = 41 scores
41/50 = 0.82
Probability of student who passed having a B = 0.20/0.82 = 0.244
Answer:
a) -7 & b) -6
Step-by-step explanation:
Here,
a) x = 0
Solution ↦
b) x = -1
Solution ↦
I believe v is your coefficient and the degree is 7
I suck at explaining but I know it’s 4
Step-by-step explanation:
using the formula :
2.d.s = V²-Vo²
2(-0.15) (60) = V² - (8.55)²
-18 = V² - 73.1
V² = 73.1 - 18
V² = 55.1
=> V = √55.1 = 7.4
so, the velocity when she ends the race =
7.4 m/s
