Question

Find any points of discontinuity for the rational function. What are the points of discontinuity? Are they all removable?

Answer 1

Factor
$\frac{(x-7)(x-3)}{(x-7)(x-3)} =1$
it simplifies to y=1
(x-7)(x-3)
they are undefined since they make the denomenator 0
solve
(x-7)(x-3)=0
x-7=0
x=7
x-3=0
x=3
restricted values are x=3 and x=7
but, the points x=3 and x=7 are holes since they were canceled out

answer is B

Answer 2

The answer would be B.