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Lesechka [4]
3 years ago
10

Find any points of discontinuity for the rational function. What are the points of discontinuity? Are they all removable?

Mathematics
2 answers:
gregori [183]3 years ago
8 0
Factor
\frac{(x-7)(x-3)}{(x-7)(x-3)} =1
it simplifies to y=1
(x-7)(x-3)
they are undefined since they make the denomenator 0
solve
(x-7)(x-3)=0
x-7=0
x=7
x-3=0
x=3
restricted values are x=3 and x=7
but, the points x=3 and x=7 are holes since they were canceled out

answer is B
Varvara68 [4.7K]3 years ago
6 0
The answer would be B.

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