For the units positions of all numbers we have:

From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:

For the tens positions of all numbers we have:

The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.

Now we insert x and z to find out y:

Now we need to find out the product of these three numbers:
Positive I think that would be it
Answer:
quadrilateral
<3
Step-by-step explanation:
Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
x=-4
y=6(-4)+23
y=-24+23
y=-1
The answer is (-4,-1)
Hopefully this helps!
Answer:
YZ=16
Step-by-step explanation:
Because they are parallel