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3 years ago

If a1 = 8 and an = an-1 + 5 then find the value of a5.

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Step-by-step explanation:

A1=8

A2=A1+5 plug 8 into A1 here. After getting the value, put into next equation. And repeat until you get A5

A3=A2+5

A4=A3+5

A5=A4+5

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Find the differential equation of the family of tangent lines to the parabola y^2 = 2x

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$\bf 
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3 years ago

Two airplanes are flying to the same airport. Their positions are shown in the graph. Write a system of linear equations that re

wariber [46]

Answer:

Airplane #1 equation: y=5/13x+42/13

Airplane #2 equation: y=1/3x+14

Step-by-step explanation:

So to find the slope of each airplane, you use the formula y2-y1/x2-x1. That means, for airplane#1 the equation will be 9-4/15-2. Simplify this and get 5/13. Then, for airplane#2, the equation will be 12-9/6-15. Simplify this and get 3/-9 and divide each side by 3 to get 1/-3 or -1/3. Next, use point slope formula to find the system of linear equations. Point slope formula is y-y1=m(x-x1). M is the slope. Use any point from the line. In this case, I will use (2,4). Tat means the first airplane's equation would be y-4=5/13(x-2). Then y-4=5/13x-10/13. Then, convert four into a fraction with a denominator of 13. This means, you have to multiply 4 by 13 to get 52/13. Add 52/13 to -10/13 to get 42/13. That means the first equation will be y=5/13x+42/13. The second equation point will be (6,12). This means the equation will be y-12=-1/3(x-6). Simplify this to get y-12=-1/3x+2. Simplify this to get y=1/3x+14. Therefore, Airplane#1 equation will be y=5/13x+42/13 and airplane #2 equation will be y=1/3x+14.

Hope this helps

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3 years ago

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1 year ago

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

this is how i got it:

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3 years ago