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2 years ago

Find the zeros of the function.

Mathematics

1 answer:

Rudik [331]2 years ago

5 0

Answer:

Lesser x = -9

Greater x = 9

Step-by-step explanation:

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Elza [17]

Answer:

8x15x12=1440

Step-by-step explanation:

7 0

3 years ago

How do you write this equation x+5=2(7+x)

True [87]

Answer:

x=-9

Step-by-step explanation:

x+5=2(7+x)

x+5=14+2x

x-2x=14-5

-1x=9

x=-9

3 0

3 years ago

Read 2 more answers

5x + 20 = -5x What does "x" equal?

True [87]

7 0

2 years ago

Read 2 more answers

Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.

Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

6 0

3 years ago

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago