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snow_tiger [21]
3 years ago
5

Solve the equations -9x + 2y = 23 and -4x - y = -3

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

Answer:

(-1,7)

Step-by-step explanation:

-9x + 2y = 23

-4x - y = -3

multiplying equation 2 by 2

-9x + 2y = 23

-8x - 2y = -6

adding the two equation to cancel out y

-17x = 17

x = -1

plugging back x = -1 into the second equation

4 - y = -3

-y = -7

y = 7

Talja [164]3 years ago
3 0

Answer:

y=7

x= -1

Step-by-step explanation:

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The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
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Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. How much interest will Juanita pay?
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Step-by-step explanation:

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Simplify the following (x-y) ² - x+y​
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How do you complete the square to rewrite y= x^ -6x + 15 in vertex form
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Vertex form of a quadratic equation is y=a(x-h)^{2}+k
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