Answer:
it affected more than half
Step-by-step explanation:
To see what are the factors use, we write each of the numbers, as product of prime factors:
![9= 3 \cdot 3\\\\ 15=3 \cdot 5\\\\ 18= 2 \cdot 9 = 2 \cdot 3 \cdot3\\\\21= 3\cdot 7\\\\30=3 \cdot10=3 \cdot 2 \cdot 5\\\\35=5 \cdot7\\\\36=6\cdot6=2\cdot3\cdot2\cdot3\\\\42=6\cdot7=2\cdot3\cdot7\\\\49=7\cdot7 ](https://tex.z-dn.net/?f=9%3D%203%20%5Ccdot%203%5C%5C%5C%5C%0A15%3D3%20%5Ccdot%205%5C%5C%5C%5C%0A18%3D%202%20%5Ccdot%209%20%3D%202%20%5Ccdot%203%20%5Ccdot3%5C%5C%5C%5C21%3D%203%5Ccdot%207%5C%5C%5C%5C30%3D3%20%5Ccdot10%3D3%20%5Ccdot%202%20%5Ccdot%205%5C%5C%5C%5C35%3D5%20%5Ccdot7%5C%5C%5C%5C36%3D6%5Ccdot6%3D2%5Ccdot3%5Ccdot2%5Ccdot3%5C%5C%5C%5C42%3D6%5Ccdot7%3D2%5Ccdot3%5Ccdot7%5C%5C%5C%5C49%3D7%5Ccdot7%0A)
As we can see, the 4 factors used to produce the numbers in the list are {2, 3, 5, 7}
Answer: {2, 3, 5, 7}
Answer:
(a) 16-2x
(b)-x-2 or x+6
(c)
Step-by-step explanation:
(a)
|6-x|+|x-10|,
|4-x|=4-x,so x<4
|2-x|=x-2=-(2-x)
2-x<0
2<x
or x>2
2<x<4
so |6-x|=6-x,in 2<x<4
|x-10|=-(x-10),in 2<x<4
|6-x|+|x-10|=6-x-(x-10)=6-x-x+10=16-2x
(b)
2-|2-|x-2||,if x<-2
|x-2|=-(x-2) if x<-2
=2-|2-{-(x-2)}|
=2-|2+x+2|
x<-2
x+2<0
=2-|x+4|
=2-(x+4),if x>-4,or -4<x<-2
=2-x-4
=-x-2
if x<-4
then |x+4|=-(x+4)
2-|x+4|=2-{-(x+4)}
=2+x+4
=x+6
Answer:
![15\sqrt{2}](https://tex.z-dn.net/?f=15%5Csqrt%7B2%7D)
Step-by-step explanation:
The formula we can use is
![d=\sqrt{2} *a](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B2%7D%20%2Aa)
Where d is the length of the diagonal and a is the length of the side of the square
Since, the floppies are in square shape and side length is 15, so a = 15
We simply put it into the formula and get length of diagonal.
![d=\sqrt{2} *a\\d=\sqrt{2} *15\\d=15\sqrt{2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B2%7D%20%2Aa%5C%5Cd%3D%5Csqrt%7B2%7D%20%2A15%5C%5Cd%3D15%5Csqrt%7B2%7D)
Hence, diagonal length is ![15\sqrt{2}](https://tex.z-dn.net/?f=15%5Csqrt%7B2%7D)
Answer:
Distribution A : 50
Distribution B : 100
Distribution C : 200
Second part is : B,C,A
Step-by-step explanation: