The diaphragm is the large flat muscle. hope that helps :)
Answer:
a) Genes b and c are farthest apart.
Explanation:
Transformation occurs when a competent bacteria cell takes up genetic material from the environment. Usually a donor cell donates its gene fragment which is then incorporated into the chromosome or plasmid of recipient bacterial cell.
Cotransformation occurs when two genes are taken up together by the recipient. The closer the genes lie to each other, more are the chances of them being taken up together. Contransformation frequency will be higher if two genes are close to each other. Here, cotransformation frequencies between three genes are given. Amongst them, the lowest frequency is 0.0064% which is present between gene b and c. Hence, gene b and c are the farthest apart.
Answer:
Explanation:
Trisodium citrate has the chemical formula of Na3C6H5O7. It is sometimes referred to simply as "sodium citrate", though sodium citrate can refer to any of the three sodium salts of citric acid. It possesses a saline, mildly tart flavor. It is mildly basic and can be used along with citric acid to make biologically compatible buffers
Sodium citrate is chiefly used as a food additive, usually for flavor or as a preservative. Its E number is E331. Sodium citrate is employed as a flavoring agent in certain varieties of club soda. It is common as an ingredient in bratwurst, and is also used in commercial ready-to-drink beverages and drink mixes, contributing a tart flavor. It is found in gelatin mix[clarification needed], ice cream, yogurt, jams, sweets, milk powder, processed cheeses, carbonated beverages, and wine[citation needed], amongst others.
Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
Cation-exchange chromatography is used when the molecule of interest is positively charged, the stationary phase is negatively charged and positively charged molecules are loaded to be attracted to it. So, the amino acids with negative charge will elute the first. Glutamate, leucin, arginine is the order of elution because of their pI values ~3, ~6 ~10.
