A new alloy is made by mixing 72 grams of iron with 9 grams of zinc. How many grams of iron are required to make the alloy when

Question

3 years ago

6

combined with 144 grams of zinc?
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2 answers:

Margaret [11] · Answer 1 · 2022-08-25T15:24:21+03:00

6 0

Answer: B) 1,152 grams

Step-by-step explanation:

144/9=16

16x72= 1,152

iren2701 [21] · Answer 2 · 2022-08-25T14:20:10+03:00

1152 grams of iron are required to make the alloy when combined with 144 grams of zinc

Step-by-step explanation:

We will use the proprtion to solve the problem

Let x2 be the quantity of iron when combined with 144 grams of zinc

So,

zinc in first alloy = z1 = 9 gm

Iron in first alloy = x1 = 72 gm

Zinc in second alloy = 144 gm

So,

$x_1:z_1::x_2:z_2\\72:9:: x_2 : 144\\\frac{72}{9} = \frac{x_2}{144}\\8 = \frac{x_2}{144}\\x_2 = 144*8\\x_2 = 1152$

Hence,

1152 grams of iron are required to make the alloy when combined with 144 grams of zinc

Keywords: Fractions, proportion

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