Answer:
Unit rates are expressed as a quantity of 1, such as 3 feet per second or 6 miles per hour, they are called unit rates.
In the given table shows the number of pictures taken and how much time it took.
For first camera;
Number of pictures (unit rate) per second = 
pictures.
For second Camera:
Number of picture per second = 
pictures.
For third Camera:
Number of picture per second = 
pictures.
The camera that takes picture the fastest is, Second Camera.
(a)
As per the given statement: At Davidson's Bike rentals, it costs $29 to rent a bike for 8 hour.
⇒ unit rate per dollar = 
hours
Therefore, 0.227 hours (nearest to hundredths) of bike use does a customer get per dollar.
(b)
Jessica bought 18 pounds of sugar for $10.
unit rate per dollar = 
therefore, 1.8 pounds of sugar did she get per dollar.
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Hmm I would say x=q
Hope this helps u <3
First we have to find p(AnB)
P(A/B)=p(AnB)/p(A)
P(AnB)=p(A) x p(A/B)
P(AnB)=0.5 x 0.4 = 0.2
Then to find p(B)
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.5+p(B)-0.2
0.6=0.3+p(B)
P(B)=0.6-0.3=0.3
Your answer is B. 12.
12 kids are unaccounted for after you subtract the kids that take A1, then A2, the both subjects.
