Answer:
Yes, P(A) = P(A|B)
Step-by-step explanation:
The context of the question is incomplete but I've assumed logically what it might be;
Whether a traveller flies or doesn't fly to their destination is unrelated to whether they home share or not;
Therefore, they are independent;
Independent events are events where the outcome of one event has no effect on the probabilities of the outcomes from a second event;
This can be represented mathematically as: P(A) = P(A|B);
The corollary of this is P(B) = P(B|A);
A common example easily understood would be if you flip a coin, there is a 50% chance of heads and 50% chance of tails;
If I flip and gets a heads first, the probability of getting a heads or tails on the second, third or tenth flip is going to be unchanged, i.e. 50% chance of heads and 50% chance of tails
The last graph is the correct graph for the problem
Answer: stop pay attention in class
Step-by-step explanation:
Amount of decreased water = 3/10
Then, it would be 3/10 * 100 = 30%
So, your answer is 30%
First, let's put the second equation, <span>x-2.23y+10.34=0, in terms of y:
x - 2.23y +10.34 = 0
2.23y = x + 10.34
y = .45x + 4.64
Now we can substitute the right side of this equation for y in the first equation
</span><span>y=2x^2+8x
.45x + 4.64 = 2x^2 + 8x
Turn it into a quadratic by getting 0 on one side:
2x^2 + 8x - .45x - 4.64 = 0
2x^2 + 7.55x - 4.64 = 0 Divide both sides by 2
x^2 + 3.76x - 2.32 = 0
x =( -b +/- </span>√(b² - 4ac) ) / 2a
x =( -3.76 +/- √(14.14 + 9.28)) ÷ 2
x = .54 or -4.31
Plug the x values into y = .45x + 4.64
y = .45 (.54) + 4.64
y = 4.88 when x= .54
y = .45 (-4.31) + 4.64
y = 2.70 when x= -4.31
Solution set:
{ (0.54, 4.88) , (-4.31, 2.70) }