2 years ago

The cartesian equation, y = 4, is equivalent to the polar equation, _____.

Mathematics

1 answer:

jolli1 [7]2 years ago

4 0

This is how you would solve the question.

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PLZ HELP on THIS QUESTION

Greeley [361]

Its a rectangle cut the corners

8 0

3 years ago

Multiply the polynomials *<br> –6w(2w2 - 5)

Paul [167]

Answer:

-12w^3 + 30w.

Step-by-step explanation:

–6w(2w^2 - 5) Using the distributive law:

= -6w* 2w^2 - 6w*-5

= -12w^3 + 30w.

5 0

3 years ago

What are the steps to solve 3(x-3)+2x+9=2x + 2(x-1

Blababa [14]

Step-by-step explanation:

3x - 9 +2x + 9 = 2x - 2

5x = 2x - 2

5x - 2x = - 2

3x = - 2

x= - 2/ 3

5 0

3 years ago

A line passes through the points (1, 4) and (3,-4). Which is the equation of the line?

andrew-mc [135]

Answer:

Y=-4x+8

Step-by-step explanation:

3 0

2 years ago

suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

3 years ago