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grandymaker [24]
3 years ago
15

An atom of argon in the ground state tends not to bond with an atom of a different element because the argon atom has 1). More p

rotons than neutrons 2). More neutrons than protons. 3) a total of 2 valence electrons. 4). A total of 8?valence electrons
Chemistry
2 answers:
Gelneren [198K]3 years ago
7 0

Answer:

The correct answer is 4). A total of 8?valence electrons

Explanation:

The argon corresponds to a noble or inert gas, like Helium, and has its complete octet in the last layer.

Gnesinka [82]3 years ago
6 0

Answer:

4. A total of 8 valence electrons

Explanation:

All atom in their ground state is at the actual state of electronic configuration. Argon has 18 number of electrons therefore, representing the electronic configuration using the Spdf  rule is 1s²2s²2p6 3s²3p6 and also the configuration of argon is computed as 2 8 8 . The argon atom has fulfilled the octet rule . The valence/outer electron(8) is fully filled and therefore find it hard to give or accept any electron to form bonding.  

Elements with fully filled octet configuration are known as inert gas or noble gas because they rarely bond with other atom of elements.

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Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0
3 years ago
Name the following compound with a polyatomic ion: Na₂SO₄ *
Helga [31]

Answer:

sodium sulfate

Explanation:

For naming an ionic compound with polyatomic anion, the metal is written first using its element name followed by name of the polyatomic anion. Therefore, the compound with Na+Na+ cation and SO2−4SO42− anion is named as sodium sulfate.

6 0
3 years ago
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PLEASE HELP ASAP PLEASE
USPshnik [31]

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>

8 0
3 years ago
Please help(15 points)
Triss [41]

Answer: because they take a lot of tie to form  

4 0
3 years ago
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How many chlorine atoms are there in 12.2 g of ccl4? How many chlorine atoms are there in 12.2 of ? 4.77×1022 atoms?
mash [69]

Answer:- 1.91*10^2^3Cl atoms.

Solution:- We have been given the grams of carbon tetrachloride and asked to calculate the number of atoms of chlorine. It is a three step conversion problem. In the first we convert the grams of carbon tetrachloride to moles of it. In second step we convert moles of carbon tetrachloride to moles of chlorine and in the third step we convert the moles of chlorine to atoms of chlorine.

For grams to mole conversion we need the molar mass of the compound. Molar mass of carbon tetrachloride is 153.82 grams per mol. If we look at the formula of carbon tetrachloride then four chlorine are present in it. It means 1 mol of carbon tetrachloride has four moles of chlorine. The calculations are as follows:

12.2gCCl_4(\frac{1molCCl_4}{153.82gCCl_4})(\frac{4molCl}{1molCCl_4})(\frac{6.02*10^2^3Clatoms}{1molCl})

= 1.91*10^2^3Cl atoms

So, there are 1.91*10^2^3Cl atoms in 12.2 grams of CCl_4 .

6 0
3 years ago
Read 2 more answers
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