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SSSSS [86.1K]
2 years ago
11

Is phosphorus dissolving in carbon disulfide a chemical or physical change?​

Chemistry
1 answer:
Shkiper50 [21]2 years ago
6 0

Phosphorus dissolving in carbon disulfide is a physical change.

A chemical change results from a chemical reaction, in which the nature of the substance is altered. On the other hand, a physical change is when matter changes forms but not chemical identity.

When phosphorus dissolves in carbon disulfide, it changes its state of aggregation, but not its nature. Thus, this is a physical change.

Phosphorus dissolving in carbon disulfide is a physical change.

You can learn more about physical and chemical changes here: brainly.com/question/13620149

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Consider a bent molecule, such as H2Se, in which the central atom has two lone pairs of electrons. The electronegativities of H
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Answer:

Based on these values and on consideration of molecular geometry, the H-Se bond can be considered almost _____non-polar___ and the molecule is __polar_____.

Explanation:

Looking at the difference in electro negativity of the two elements; hydrogen and selenium, one may be led to the conclusion that the molecule is nonpolar since the magnitude of electronegative between the two bonding atoms is minimal.

However, electro negativity difference alone is insufficient to determine the polarity of a molecule. The structure of the molecule is also considered. Based on the structure of the molecule, it is expected to have a dipole moment. Hence the molecule is polar.

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3 years ago
4Fe +302 + 2Fe2O3 <br> How many grams of Fe2O3 will be produced from 10.0 g of Fe and 7.00 g of O2?
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Explanation:

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3 years ago
How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2
jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol

For the given chemical reaction:

BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = \frac{1}{1}\times 0.00286mol=0.00286mol of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

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