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SSSSS [86.1K]
2 years ago
11

Is phosphorus dissolving in carbon disulfide a chemical or physical change?​

Chemistry
1 answer:
Shkiper50 [21]2 years ago
6 0

Phosphorus dissolving in carbon disulfide is a physical change.

A chemical change results from a chemical reaction, in which the nature of the substance is altered. On the other hand, a physical change is when matter changes forms but not chemical identity.

When phosphorus dissolves in carbon disulfide, it changes its state of aggregation, but not its nature. Thus, this is a physical change.

Phosphorus dissolving in carbon disulfide is a physical change.

You can learn more about physical and chemical changes here: brainly.com/question/13620149

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4 years ago
25.0 ml of a 6.0 m hno3 stock solution is diluted using water to 100 ml. How many moles of hno3 are present in the dilute soluti
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Answer:

The answer to your question is: 6 moles of HNO₃

Explanation:

Data

Volume = 25 ml

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Formula

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# of moles = Volume x Molarity

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Calculate the enthalpy change for the reaction Mn3O4(s)+CO(g)⟶3MnO(s)+CO2(g) from the following:
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Answer:

- 50.7 kJ.

Explanation:

  • To get the enthalpy change for the reaction:

Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).

  • We must orient the given reactions in a way that its sum give the required reaction.

The first reaction be as it is:

Mn₃O₄(s) + 4CO(g) ⟶ 3Mn(s) + 4CO₂(g), <em>ΔH₁ = 255.6 kJ.</em>

The second reaction should be reversed and multiplied by 3 and also the value of its ΔH must multiplied by (- 3):

3Mn(s) + 3CO₂(g) ⟶ 3MnO(s) + 3CO(g), <em>ΔH₂ = (- 3)(102.1 kJ) = - 306.3 kJ.</em>

  • By summing the two reactions after the modification, we get the required reaction:

<em>Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).</em>

<em></em>

<em>∴ ΔH rxn = ΔH₁ + ΔH₂ = (255.6 kJ) + (- 306.3 kJ) = - 50.7 kJ.</em>

3 0
3 years ago
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