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Dominik [7]
4 years ago
11

If the pattern below follows the rule "Starting with three, every consecutive line has a number one more than the previous line,

" how many marbles must be in the seventh line?
Mathematics
2 answers:
mr Goodwill [35]4 years ago
8 0

Answer: 10 (apex)  !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!                                                                            

Afina-wow [57]4 years ago
5 0
We are asked to determine how many marbles must be in the seventh line but the condition stated in the problem must be followed such that "starting with a number in every consecutive line it has a number one more than the previous line". 
We start with 3, followed by 3+1 = 4, followed by 4+1=5, followed by 5+1=6, followed by 6+1=7, followed by 7+1=8, followed by 8+1=9
The sequence is:
3,4,5,6,7,8,9
In the seventh, there are 9 total marbles.
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Maurinko [17]
LCM stands for least common multiple. We are being asked to find the lowest multiple that 6 and 15 have in common.

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6: 6, 12, 18, 24, 30, 36

15: 15, 30, 45, 60, 75, 90

The LCM of 6 and 15 is 30.
5 0
4 years ago
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Please answer it. Thank you
Finger [1]

Answer:

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3 years ago
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tatyana61 [14]

Answer:

two solutions : (-3;4)  and (-5;6)

Step-by-step explanation:

hello :

X²+y²+18x+29=0    ..(1)

X+y=1 ...(2)

by (2) : y = 1 - x

put this value in (1) : x² +(1-x)² +18x+29 = 0

x² +1 +x² -2x+18x +29 =0

2x²+16x +30 = 0

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delta = b²-4ac     a=1   b=8   c = 15

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case 2 : x = -5    y = 1 - (-5) = 6

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3 years ago
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Step-by-step explanation:

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