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Nat2105 [25]
3 years ago
14

The American Academy of Periodontology released a survey, revealing that 27% of US adults admit they lie to their dentist about

how often they floss their teeth. Periodontist Dr. Garcia believes that the percentage seems low, so he decides to conduct his own hypothesis test to determine the true proportion. What should he write as the null and alternative hypotheses for this situation?
Answer Options:
A: H0: p = 0.27; Ha: p > 0.27

B: H0: p = 0.27; Ha: p < 0.27

C: H0: p = 0.27; Ha: p ≠ 0.27

D: H0: μ = 0.27; Ha: μ > 0.27

E: H0: μ = 0.27; Ha: μ < 0.27
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

A: H0: p = 0.27; Ha: p > 0.27

Step-by-step explanation:

The parameter is the population proportion.

According to the survey conducted by the American Academy of Periodontology, the proportion of of US adults who admit they lie to their dentist about how often they floss their teeth is 27%.

This means the null hypothesis is :

H_0: p=0.27

Periodontist Dr. Garcia believes that the percentage seems low, so his claim is that the percentage should be more than 27%.

This means, the alternate hypothesis is

H_{a}:p \: > \: 0.27

Therefore the correct choice is A.

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2 years ago
Please help!!!!!!!!!!!!!!!! 100pts,
Helga [31]

QUESTION:

The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.

ANSWER:

Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–

  • P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.

Since there are 10 digits to choose from, we can assume that n = 10.

Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.

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3 0
2 years ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
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jenyasd209 [6]

Answer:

hi it's

Easy B

Step-by-step explanation:

No Problem

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