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Ket [755]
3 years ago
14

A major fishing company does its fishing in a local lake. The first year of the company's operations it managed to catch 75,000

fish. Due to population decreases, the number of fish the company was able to catch decreased by 8% each year. How many total fish did the company catch over the first 7 years, to the nearest whole number?
Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

The total amount of fishes  caught is 414,519 fishes

Step-by-step explanation:

Here, given the percentage decrease in the population of fishes, we want to know the total amount of fishes caught by the company in the first 7 years.

First year, we have 75,000 fishes

Second year, we would have 75,000 - (8% of 75,000) = 75,000 - (0.08 × 75,000) = 75,000 - 6,000 = 69,000

Third year, we would have 69,000- (0.08 × 69,000) = 69,000 - 5520 = 63,480

Fourth year, we would have 63,480 - (0.08 × 63,480) = 58,401.6

Fifth year, we would have 58,401.6 - (0.08 × 58,401.6) = 58,401.6 - 4,672.18 = 53,729.472

Sixth year, we would have 53,729.472 - (0.08 × 53,729.472) = 53,729.472 - 4,298.3578 = 49,431.114

Seventh year, we would 49,431.114 - (0.08 × 49,431.114) = 45,476.625

The addition of all these values will give the total number of fishes caught = 75,000 + 69,000 + 63,480 + 58,401.6 + 53,729.472 + 49,431.114 + 45,476.625 = 414,518.8 = 414,519 fishes to the nearest whole number

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