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Natali [406]
3 years ago
12

What is the area of the rectangle if the side lengths are 3xy and 4x^2y^3

Mathematics
1 answer:
LiRa [457]3 years ago
4 0
4x - 1 = side of square 2x + 1 = length of rectanglex + 2 = width of rectangleSince their perimeters are equal, 4(4x - 1) = 2(2x + 1) + 2(x + 2) 16x - 4 = 4x + 2 + 2x + 410x = 10x = 1If we plug 1 in for x,Each side of the square is 4(1) - 1 = 3The perimeter is thus 12 The length of the rectangle = 2(1) + 1 = 3The width of the rectangle is 1 + 2 = 3The perimeter is this 2(3) + 2(3) = 12 So x = 1 is the verified. 

hope this helps! (:
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Step-by-step explanation:

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Answer:

x = \sqrt{w(w+z)}

Step-by-step explanation:

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Expanding out the left side, w^2 + 2wz + z^2 = x^2 + v^2.

Now substitute the equation from before, v^2 = x^2 - w^2 + z^2, into the new equation.

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