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Zarrin [17]
3 years ago
13

Quadrilateral QRST has diagonals that are perpendicular but not congruent. Which type of quadrilateral could describe quadrilate

ral QRST?
A. Square
B. Rhombus
C. Isosceles trapezoid
D. Rectangle
Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer: rhombus

Step-by-step explanation: because trump is the best president

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Determine the rate of change for 6y=8x-40
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3 years ago
5. Solve the equation z^2 + 4z - 9 = 0 by completing the square.
Luba_88 [7]

Answer:

A. Z = 2 + N13

Step-by-step explanation:

Let's solve your equation step-by-step.

0=z2+4z−9

Step 1: Subtract z^2+4z-9 from both sides.

0−(z2+4z−9)=z2+4z−9−(z2+4z−9)

−z2−4z+9=0

For this equation: a=-1, b=-4, c=9

−1z2+−4z+9=0

Step 2: Use quadratic formula with a=-1, b=-4, c=9.

z=

−b±√b2−4ac

2a

z=

−(−4)±√(−4)2−4(−1)(9)

2(−1)

z=

4±√52

−2

z=−2−√13 or z=−2+√13

8 0
3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
3 years ago
Solve using a proportion and an equation. Kendra found the experimental probability of her making a penalty kick in soccer is 3/
muminat

Answer: The predicted number of penalty kicks = 12

Step-by-step explanation:

Given : The experimental probability of her making a penalty kick in soccer is 3/10 or 30%.

So, the proportion of penalty kicks she make = 0.3

Out of 40 penalty kicks, the predicted number of penalty kicks = 0.3 x 40

= 12

Hence, the predicted number of penalty kicks = 12

7 0
3 years ago
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