Ask question

Ask question

All categories

3 years ago

13

Quadrilateral QRST has diagonals that are perpendicular but not congruent. Which type of quadrilateral could describe quadrilate

ral QRST?
A. Square
B. Rhombus
C. Isosceles trapezoid
D. Rectangle

1 answer:

Serggg [28]3 years ago

8 0

Answer: rhombus

Step-by-step explanation: because trump is the best president

You might be interested in

Cuanto es +(+9) - (+6)

ki77a [65]

+(+9)-(+6)
(+9)-(+6)
9-6
3

5 0

3 years ago

Read 2 more answers

A train travels from Tutuban to Calamba station. The distance between Tutuban and Calamba is defined by the function d(x) = x4 +

svlad2 [7]

given :

d(x) = x^4 + x^3 + 3x^2 + 4x - x kilometers.

t(x) = x

presumably the same value of x is used in both equations.

distance traveled is a function of time traveled, and that this relationship is preserved for any given speed.

Formula

r × t = d

r is the rate in kilometers per hour.

t is the time in hours.

d is the distance in hours.

based on the formulas you are given, this becomes:

r * t(x) = d(x)

if the train travels for 2 hours, then:

t(x) = t(2) = 2

d(x) = x^4 + x^3 + 3x^2 + 4x - x

d(2) = 2^4 + 2^3 + 3*2^2 + 4*2 - 2

d(2) = 42.

hence, t(2) = 2 and d(2) = 42

if the trip takes 2 hours, then the distance traveled is 42 kilometers based on the value of x = 2 in both equations.

the rate * time = distance equation of r * t(x) = d(x)

r × 2 = 42

r = 42/2

= 21.

this says the train will travel 42 kilometers in 2 hours if the train travels at 21 kilometers per hour.

4 0

3 years ago

What is the measure of WX shown in the diagram below

Alexxandr [17]

Answer:

D. $32^{\circ}$

Step-by-step explanation:

We have been given an image of a circle. We are asked to find the measure of arc WX.

Upon looking at our given diagram, we can see that angle S is formed by intersecting secants outside the circle.

We will use intersecting secants theorem, which states that measure of an angle formed by two intersecting secants outside a circle is half the difference of intercepted arcs.

Using above theorem, we can set an equation to find the measure of arc WX as:

$m\angle S=\frac{\text{Major Arc-Minor Arc}}{2}$

$41^{\circ}=\frac{114^{\circ}-WX}{2}$

$2*41^{\circ}=\frac{114^{\circ}-WX}{2}*2$

$82^{\circ}=114^{\circ}-WX$

$82^{\circ}-114^{\circ}=114^{\circ}-114^{\circ}-WX$

$-32^{\circ}=-WX$

$WX=32^{\circ}$

Therefore, the measure of arc WX is 32 degrees and option D is the correct choice.

4 0

3 years ago

According to these three facts, which statements are true?

Yanka [14]

Q1) We have the following statements:

<span>1. Circle W has center (−3, 0) and radius 8.

We can write this statement as the following equation:

</span> $(x-h)^2+(y-k)^2=r^2 \therefore (h,k)=(-3,0) \ and \ r=8 \\ \\ \therefore (x+3)^2+y^2=64$
<span>
The graph of this equation is shown in Figure 1.

</span><span>2. Circle V is a translation of circle W, 2 units down.

To do this translation we add two units to the y-coordinate, so:

</span> $(x+3)^2+(y+2)^2=64$
<span>
The graph is shown in Figure 2.

</span><span>3. Circle V is a dilation of circle W with a scale factor of 2.

To do this dilatation we multiply both the center and the radius by the scale factor of 2, thus:

</span> $(x+3)^2+y^2=64 \\ (h,k)=(-3,0) \\ (h_v,k_v)=2\times (-3,0)=(-6,0) \ and \ r_v=8\times2=16 \\ \\ (x+6)^2+y^2=256$
<span>
This circle is shown in Figure 3

So let's analyze each statement.

Q1.1) </span><span>The center of circle V is (−5, 0).

This is false. From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0).

Q1.2) </span><span>Circle V and circle W are similar.

Since all circles have the same shape even though they may be different sizes, then all circles are similar. Therefore, it is true that circle V and circle W are similar.

Q1.3) </span><span>The radius of circle V is 16.

From the statement 3 we can affirm that this is true. By applying the dilatation </span><span>with a scale factor of 2 we find out that the radius of the new circle is in fact equal to 16.

Q1.4) </span>Circle V and circle W have the same center.

From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0). On the other hand, the center of circle W is (-3, 0). From this, it follows that this statement is false.

Q2) Suppose x is any positive number.

We have two concentric circles as follows:

$x\ \textgreater \ 0 \\ \\ Circle \ 1: Center \ (0,0) \ and \ radius \ 2x \\ \\ Circle \ 2: Center \ (0, 0) \ and \ radius \ 10x$ <span>

Q2.1) Why is circle 1 similar to circle 2?
</span><span>
If we perform a dilatation, that is, a </span>resizing of one circle, centered on the shared center, until both circles overlap, it will be true that the circles will always overlap no matter what size they are, thus, they are similar. In fact, as we said in above all circles are similar.

Q2.2) <span>Circle 2 is a dilation of circle 1 with a scale factor of 0.2.

Suppose that:

</span> $x=2$
<span>
Then circle 1 is given by the following equation:

</span> $x^2+y^2=4$
<span>
If we dilate this circle </span><span>with a scale factor of 0.2 then:

</span> $Circle \ 1: x^2+y^2=4 \\ Diameter \ 1=2r=2\times 2=4 \\ \\ (h,k)=(0,0) \\ (h_v,k_v)=0.2\times (0,0)=(0,0) \ and \ r_v=0.2\times 2=0.4 \\ \\ Circle \ 2:x^2+y^2=0.16 \\ Diameter \ 2=2\times 0.4=0.8 \\ \\ So: \\ \\ Diameter \ 1 \neq Diameter \2$
<span>
So the statement b</span>oth circles have congruent diameters is false.

<span>Q2.3) Circle 2 is a dilation of circle 1 with a scale factor of 5.

We have the same equation for circle 1:

</span> $x^2+y^2=4$

$Circle \ 1: x^2+y^2=4 \\ \\ Dilatation: \\ (h,k)=(0,0) \\ (h_v,k_v)=5\times (0,0)=(0,0) \ and \ r_v=5\times 2=10 \\ \\ Circle \ 2:x^2+y^2=100$

Two circles have the same area if they have the same radius. Given that this is no applied to our circles, the statement circle 1 and circle 2 have equal areas is false.

8 0

3 years ago

From the choices below, choose an expression that is equivalent to the expression below

Sergio [31]

Answer:.

Step-by-step explanation:

7 0

2 years ago