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Illusion [34]
3 years ago
11

Help.. ill give brainliest..

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

(-6)-(+2)= -8

(-9)-(-8)= -17

(-6)-(+6)= -12

(-8)-(-8)= -16

(+5)-(+1)= 4

(+6)-(-2)= 8

(-3)-(+5)= -8

(-8)-(+5)= -13

(-9)-(-4)= -13

(+1)-(+3)= -2

(-3)-(+8)= -11

(+9)-(-4)= 13

(+8)-(-7)= 15

(-6)-(+3)= -9

(-3)-(+4)= -7

(-4)-(+3)= -7

(-6)-(+1)= -7

(+8)-(-8)= 16

(+1)-(+4)= -3

(+7)-(+9)= -2

(+5)-(-5)= 10

(+6)-(-9)= 15

(+7)-(-5)= 12

(+2)-(+1)= 1

(-6)-(+3)= -9

(+2)-(+9)= -7

(+1)-(+1)= 0

(-2)-(+3)= -5

(+3)-(+4)= -1

(+8)-(-9)= 17

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Step-by-step explanation:

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Let a_n be the n th digit after the decimal point in
WITCHER [35]
I believe this should just be equal to<span>
9π+5e−<span>(<span>⌊9π+5e⌋</span>)</span>=9π+5e−41</span>
The first element in your sum should be the first digit after the decimal point times .1, so you have
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The next element in the sum is the second digit after the decimal place times .01, so you get<span>
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
5 0
3 years ago
How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!
Hitman42 [59]
The i in the denominator is missing in the second expression. It should be

\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}

This follows from

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