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borishaifa [10]
3 years ago
9

8.

Mathematics
2 answers:
otez555 [7]3 years ago
5 0
Since the argument of the sine function is x without any scaling factor, the period is 2π, the 1st selection.
Dennis_Churaev [7]3 years ago
3 0
The period for a sine function is always 2pi/a where y=sin ax   
If y= 3sinx then a=1 so 2pi/1=2pi 
 2pi =period
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Answer:

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9514 1404 393

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