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Marianna [84]
1 year ago
12

Which statement corrects the error, or errors, in this definition?In a dilation, each point in the pre image and it’s correspond

ing point in the image are at equal distances from the given line. Also the line segment joining two such points is perpendicular to the given line.A. The dilation is correctB. A dilation is when a object moves in a circular arc around a pointC. A dilation properly stretches or compresses an object based on a given scale factor D. A dilation moves points a specified distance along a line parallel to a specified line
Mathematics
1 answer:
Serggg [28]1 year ago
7 0

Remember that a dilation stretches or compresses an object based on a given scale factor, therefore, the correct option is C

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Please help! NO FAKE ANSWERS PLEASE!!!!!
vredina [299]
Ninety nine percent hope this helps!

Sorry if it didn’t :c
8 0
2 years ago
(b) The force, F, between two objects is inversely proportional to the square of the distance, d, between
LiRa [457]

Answer:

F is reduced by 31%

Step-by-step explanation:

F = 1/(d²)

now, we increase the distance by 20% (multiply by 1.2).

F new = 1/(1.2×d)² = 1/(1.44×d²) = (1/1.44) × (1/(d²)) =

= 1/1.44 × old F = 0.69 × old F

100 - 69 = 31%

6 0
3 years ago
the value of a collectible coin can be represented by the equation y=2x+9.74 where x represents the number of years that consuel
Serggg [28]

Answer:

The answer is b ($9.74)

Step-by-step explanation:

I got it right (:

4 0
3 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
3 years ago
What is 73% of 15 cuz i dont know what the answer is
Trava [24]

Answer:

10.95 (if you need to round 11)

Step-by-step explanation:

:p

3 0
3 years ago
Read 2 more answers
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