All categories

3 years ago

F(x) = -3x^2 -5 g(x) = 2x -5 Find f(2) x g(6)

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

F(2)= -3(2)^2-5= -3(4)-5= -12-5=-17
g(6)= 2(6)-5= 12-5=7

-17 x 7= -119 is the answer

You might be interested in

Find the equation of the sphere passing through P(negative 4 comma 7 comma 6 )and Q(8 comma negative 3 comma 5 )with its center

Juli2301 [7.4K]

Answer: The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

Step-by-step explanation:

The centre of the sphere is the midpoint of the diameter, which is

1/2

[(-4,7,6) + (8,-3,5)] =(2,2,5/2)

The length of the diameter is

=sqrt |(8,-3,5) - (-4,7,6)|^2

=sqrt (12^2 + (-10)^2 + (-1)^2)

=sqrt (144+100+1)

=sqrt(245)

so the radius of

the sphere is:

1/2(sqrt(245)) = sqrt(245)/2.

The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

4 0

3 years ago

Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the r

Wewaii [24]

Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28

Answer: 28

8 0

3 years ago

A hockey team wants to sell $500 worth of tickets. If each ticket costs $10, how many tickets

Tanzania [10]

Given ,

Hockey team wants to sell 500$ worth of tickets

Cost of each ticket = $10

To meet its goal ,
Number of tickets to be sold = total cost/cost of one ticket

=> Number of tickets to be sold = 500/10 = 50 tickets .

5 0

2 years ago

Read 2 more answers

What are the two smallest consecutive odd integers whose sum is greater than 17

Mice21 [21]

Answer:

9 and 11

Step-by-step explanation:

5 0

3 years ago

Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

3 0

2 years ago