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N76 [4]
3 years ago
14

Write the equation of this circle in standard form. A) (x - 2)2 + (y - 3)2 = 4

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

x^2 + y^2 -4x -6y + 9 = 0

Step-by-step explanation:

To write a circle in standard form, expand the equation of the circle and move all terms to one side.

(x-2)^2 + (y-3)^2 = 4\\x^2 -4x + 4 + y^2 -6y + 9 = 4\\x^2 +y^2 - 4x - 6y + 13 = 4\\x^2 + y^2 -4x -6y + 9 = 0

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If f(x) = -3 3 and g(x)= 4x2 + 2x - 4, find (f +g)(x).<br>​
alina1380 [7]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = x/4 - 3

g(x) = 4x² + 2x - 4

(f + g)(x) is f(x) + g(x)

<u>Step 2: Find</u>

  1. Substitute in functions:                                                                                     (f + g)(x) = x/4 - 3 + 4x² + 2x - 4
  2. Combine like terms:                                                                                         (f + g)(x) = 4x² + 9x/4 - 7
3 0
3 years ago
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