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Ludmilka [50]
2 years ago
9

What % of $10 = $2??????

Mathematics
1 answer:
Len [333]2 years ago
8 0

Answer:

20% of 10= 2 is the answer

hope this helps!

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Number 1 The population of bacteria triples every day.
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In the ratio 3:7 Zoe received £24 how much did Hannah receive last week
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Zoe received £24 (3 x 8 = 24)

</span>Hannah 7 x 8 = £56
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[A] is making 25 sundaes with mint, chocolate, and vanilla ice cream.
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What is 1 6\10+ 5 2\10(what is 6\8- 2 4\8)what is 6 6\10- 4 4\10​
padilas [110]

Answer:

what is 1 6/10+5 2/10

=16/10 + 52/10 =

<u>16+52   =  68</u>

10              10

6/8-24/8

=6/8-20/8

<u>6-20 =  14</u>

8           8

6 6/10- 4 4/10

=<u>66-44 = 22</u>

10           10

Step-by-step explanation:

1/ if the fraction is mixed number example 2 1/7, it will be 2x7+1 and that will be 15 over 7

2/and if the bottom number example: 2 1/7, 7 is the bottom number and if 2 1/3 (3 is the bottom number) then see what the bottom number have in common example: 7-x1=7

7x2=14

7x3=21

3x1=3

3x2=6

3x3=9

3x4=12

3x5=15

3x6=18

3x7=21

so 21 is 7 and 3 have in common so the bottom number which is now 21 will divide 7 and got 3 and 3 will go on the top number 1 and 21 divide 3 which is 7 will go on the top number 1 and you continue to add your sum or subtract understand or not

4 0
2 years ago
Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su
Alja [10]

Answer:

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

Step by step explanation:

\frac{ {(4 {n}^{4} {q}^{5})}^{2}  {(8 {n}^{4} q)}^{-2} }{  {(- 3 {nq}^{9})}^{ - 1}   {(4 {n}^{3} {q}^{9})  }^{3} }

first we will change the terms with negative superscrips to the other side of the fraction

\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }

then we will distribute the superscripts

\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2}  {q}^{2} }

\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8}  {q}^{2} }

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

{4}^{2 - 3}  {q}^{10  + 9 - 2 - 27}  {n}^{8 + 1 - 8 - 9}  {8}^{ - 2}  { (- 3)}^{1}

{4}^{ - 1}  {q}^{ - 10}  {n}^{ - 8}  {8}^{ - 2}  { (- 3)}^{1}

then we will change again the terms with negative superscrips to the other side of the fraction

\frac{ - 3}{ 4 \times  {8}^{2}  {q}^{10} {n}^{8}  }

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

4 0
2 years ago
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