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3 years ago

Max says that the elapsed time from 11:55 AM to 1:01 PM is more than an hour and a half. Is he correct ? Explain.

1 answer:

5 0

He is wrong because 12:55 is one hr and you still need to get to 1:25 but he only got to 1:01 so he did not get the correct answer

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If A = { a, b, c, d} and B = {b,c,d,e} Then find AnB {b,c,d}

vladimir1956 [14]

Answer:

AnB = ( b, c, d ) is the answer.

Hope this will help u

5 0

3 years ago

Can someone answer this for me? Thanks!

MrRa [10]

Hiii :))

Answer is in the attachment.

Identity used :-

1) cosec² α = 1 + cot² α

Trigonometric Ratio :-

1) cot 30° = √3

_____

Reddam is an expensive school, right?

RainbowSalt2222 ☔

4 0

2 years ago

Read 2 more answers

If j and k are parallel lines, A and B are points on j, and C and D are points on k, how many planes contain points A, B, C, and

natita [175]

A and B are points on j.

C and D are points on k.

Join AD and BC.

ABCD is a quadrilateral.

Clearly, the quadrilateral ABCD is the only plane that contains the points A, B, C and D.

Hence, correct answer is option A. Exactly one.

8 0

3 years ago

1+14554345555556675566669877

zhenek [66]

14554345555556675566669878 is your answer.

All you have to do when adding 1 is add the number at the very end of the number +1.

It's quite easy.

Glad I could help, and good luck!

8 0

3 years ago

Read 2 more answers

Solve the equation. StartFraction dy Over dx EndFraction equals5 x Superscript 4 Baseline (1 plus y squared )Superscript three h

dangina [55]

Answer:

Step-by-step explanation:

To solve the differential equation

dy/dx = 5x^4(1 + y²)^(3/2)

First, separate the variables

dy/(1 + y²)^(3/2) = 5x^4 dx

Now, integrate both sides

To integrate dy/(1 + y²)^(3/2), use the substitution y = tan(u)

dy = (1/cos²u)du

So,

dy/(1 + y²)^(3/2) = [(1/cos²u)/(1 + tan²u)^(3/2)]du

= (1/cos²u)/(1 + (sin²u/cos²u))^(3/2)

Because cos²u + sin²u = 1 (Trigonometric identity),

The equation becomes

[1/(1/cos²u)^(3/2) × 1/cos²u] du

= cos³u/cos²u

= cosu

Integral of cosu = sinu

But y = tanu

Therefore u = arctany

We then have

cos(arctany) = y/√(1 + y²)

Now, the integral of the equation

dy/(1 + y²)^(3/2) = 5x^4 dx

y/√(1 + y²) = x^5 + C

y - (x^5 + C)√(1 + y²) = 0

is the required implicit solution

5 0

3 years ago