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yulyashka [42]
3 years ago
13

State which of the following ordered pairs is a function. Set A: (-1, 0), (-2, 1), (4, 3), (3, 4) Set B: (1, 4), (2, 3), (3, 2),

(4, 1) Set C: (2, 1), (3, 2), (2, 3), (1, 4)
Mathematics
2 answers:
scZoUnD [109]3 years ago
5 0
It would be set A and B. They are both functions.

Hope This Helps You!
Good Luck Studying :)


liubo4ka [24]3 years ago
4 0
Sets A and B are both functions because they all have different x values. Set C is not a function because it repeats the x value of 2 and gives it two different y values.
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Which of the binomials below is a factor of this trinomial?
8_murik_8 [283]

Answer:

C. x - 4

Step-by-step explanation:

The best way to do this is to first take out GCF

6(x² - x - 12)

Then we factor

6(x - 4)(x + 3)

We can now see our answer.

8 0
3 years ago
Read 2 more answers
What is the mean for the following set of data?<br> 2,5, 7, 8, 11, 11, 12<br> 10<br> 11<br> 8
Yuri [45]
Add up all the numbers & divide by the number of numbers. That should give you the mean.
4 0
3 years ago
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The saucer for Roger's teacup has a radius of 3 centimeters. What is the saucer's circumference?
Fantom [35]

C=dπ and r+r=d so 3+3=6 and 6π≈18.84 so the circumference would be 18.84
7 0
3 years ago
Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer in each box.
stealth61 [152]

Answer:

The coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

Step-by-step explanation:

The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:

  • x-coordinate of the point does not change, but
  • y-coordinate of the point changes its sign

In other words:

The point P(x, y) after reflection across x-axis would be P'(x, -y)

P(x, y)        →       P'(x, -y)

Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:

P(x, y)        →       P'(x, -y)

A(2, 3)       →       A'(2, -3)      

B(5, 5)       →       B'(5, -5)

C(7, 3)        →      C'(7, -3)

D(5, 2)       →       D'(5, -2)

Therefore, the coordinates of ABCD after  the reflection across the x-axis would become:

  • A'(2, -3)
  • B'(5, -5)
  • C'(7, -3)
  • D'(5, -2)

8 0
3 years ago
How to inverse this function step by step <br> f(x)=x-3/5
Nitella [24]

f(x)=x3−5

Replace f(x)

with y

.

y=x3−5

Interchange the variables.

x=y3−5

Solve for y

.


Since y

is on the right side of the equation, switch the sides so it is on the left side of the equation.

y3−5=x

Add 5

to both sides of the equation.

y3=5+x

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

y=3√5+x

Solve for y

and replace with f−1(x)

.


Replace the y

with f−1(x)

to show the final answer.

f−1(x)=3√5+x

Set up the composite result function.

f(g(x))

Evaluate f(g(x))

by substituting in the value of g into f

.

(3√5+x)3−5

Simplify each term.


Remove parentheses around 3√5+x

.

f(3√5+x)=3√5+x3−5

Rewrite 3√5+x3

as 5+x

.

f(3√5+x)=5+x−5

Simplify by subtracting numbers.

.

Subtract 5

from 5

.

f(3√5+x)=x+0

Add x

and 0

.

f(3√5+x)=x

Since f(g(x))=x

, f−1(x)=3√5+x is the inverse of f(x)=x3−5

.

f−1(x)=3√5+x

5 0
3 years ago
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