As a disclaimer, I can't say I'm completely confident in this answer. Use at own risk.
Formulas:
Year 1: 328,000 (sales) - 117,000 (expense) = 211,000 (profit)
Year 2: 565,000 (sales) - x (expense) = y (profit)
Net Profit: 211,000 + y = 113,000
Math
211,000 (profit y1) + 565,000 (sales y2) = 776,000
776,000 - 113,000 (net profit) = -663,000 (expenses)
Confirm:
Net Profit: 211,000 + y = 113,000 (listed in formulas, just a reminder)
Plug in: 565,000 (y2 sales) - 663,000 (our solution) = -98,000
211,000 (y1 net) + -98,000 (our plug in) = 113,000 (2 year net profit given to us)
(6x-1)+20+(x+14)=180
6x-1+20+x+14=180
6x+x+20+14-1=180
7x+33=180
-33 -33
7x=147
7/7x=147/7
x=21
Measure of angle A=:
(6x-1)
6x-1
6(21)-1
126-1
125
Measure of angle A is 125°
Measure of angle C=
(x+14)
x+14
21+14
35
Measure of angle C is 35°
(x-5)(x+7).
explanation:
(x-5)(x+7)=0
<=> x-5=0 or x+7=p
<=> x=5 or x=-7
x +y = 81 million
let x be the short stop and y be the pitcher
so pitcher (y) gets 2 times what the the shortstop (x) gets so y = 2x
so x + 2x = 81 million
3x = 81
x = 27
the short stop makes 27 million
the pitcher makes 54 million
Answer:
The ball will hit the ground at 10 seconds and its maximum height is 1024 feet.
Step-by-step explanation:
Height of a mountain, h = 90 feet
Upward velocity of a ball, u = 64 ft/s
Its height as a function of time can be written by using the second equation of motion as follows :
.....(1)
When it will hit the ground, f(x) = 0
It is quadratic equation.
t = -6 s and t = 10 s
Neglecting -6 seconds, the ball will hit the ground at 10 seconds.
For maximum height,
Put f'(x) = 0
Put t = 2 in equation (1)
Hence, the ball will hit the ground at 10 seconds and its maximum height is 1024 feet.
