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Gennadij [26K]
3 years ago
13

Divide £2400 into the ratio 5:7

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:

£1000, £1400

Step-by-step explanation:

Sum the parts of the ratio 5 + 7 = 12 parts

Divide the amount by 12 to find the value of one part of the ratio.

£2400 ÷ 12 = £200, thus

5 parts = 5 × £200 = £1000

7 parts = 7 × £200 = £1400

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Answer:

The tall of the flag pole is 51 ft answer (A)

Step-by-step explanation:

∵ The tall of the man = 6 ft

∵ The his shadow = 10 ft

∵ The shadow of the flag pole = 85 ft

∵ Tall of the man/tall of the flag = shadow of the man/shadow

   of the flag

∴ 6/x = 10/85 ⇒ where x is the tall of the flag

∴ x = (6 × 85) ÷ 10 = 510 ÷ 10 = 51 ft

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Step-by-step explanation:

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3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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3 years ago
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Answer:

abcdefghijklmnopqrstuvwxyz

Step-by-step explanation:

know i know my abcs why wont you sing with me

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